As shown in the figure, a current of 2 A flowing in an equilateral triangle of side 4 √3 cm. The magnetic field at the centroid O of the triangle is (Neglect the effect of earth's magnetic field)

Question

As shown in the figure, a current of 2 A flowing in an equilateral triangle of side 4 √3 cm. The magnetic field at the centroid O of the triangle is <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/7966a16eb63a2b135952354c744a3cc3-.png" /> (Neglect the effect of earth's magnetic field) (A) 4 √3 × 10-4 T (B) √3 × 10-4 T (C) 4 √3 × 10-5 T (D) 3 √3 × 10-5 T

Tardigrade Admin · Accepted Answer

d tan 60°=2 √3 d =2 cm B =3 × (μ0 i /2 π d ) sin 60° =3 × (2 × 10-7 × 2/2 × 10-2) × (√3/2) =3 √3 × 10-5

Q. As shown in the figure, a current of $2 A$ flowing in an equilateral triangle of side $43 c m$ . The magnetic field at the centroid $O$ of the triangle is

(Neglect the effect of earth's magnetic field)

$43 \times 1 0^{- 4} T$

$3 \times 1 0^{- 4} T$

$43 \times 1 0^{- 5} T$

$33 \times 1 0^{- 5} T$

$d tan 6 0^{\circ} = 23$
$d = 2 c m$
$B = 3 \times \frac{μ _{0} i}{2 π d} sin 6 0^{\circ}$
$= 3 \times \frac{2 \times 1 0 ^{- 7} \times 2}{2 \times 1 0 ^{- 2}} \times \frac{3}{2}$
$= 33 \times 1 0^{- 5}$

Q. As shown in the figure, a current of 2A flowing in an equilateral triangle of side 43​cm. The magnetic field at the centroid O of the triangle is (Neglect the effect of earth's magnetic field)

43​×10−4T

3​×10−4T

43​×10−5T

33​×10−5T