Question

As shown in figure light $P$ enters to slab at an angle $60^{\circ }$ with normal and inside slab $Q$ makes total internal reflection. Find minimum refractive index of slab.

• A. $1.72$
• B. $1.52$
• C. $1.32$
• D. $1.12$

Answer 1

Answer: (C)

At point $A$
$1sin60^{\circ }=\mu sinr\Rightarrow sinr=\frac{\sqrt{3}}{2\mu }$
At point $B$
$sin\left(90^{\circ }-r\right)>sinC$
$\Rightarrow cosr>\frac{1}{\mu }\Rightarrow \sqrt{1-\frac{3}{4{\mu }^2}}>\frac{1}{\mu }$
$\Rightarrow 1-\frac{3}{4{\mu }^2}>\frac{1}{{\mu }^2}\Rightarrow 1>\frac{7}{4{\mu }^2}$
$\Rightarrow {\mu }^2>\frac{7}{4}\Rightarrow \mu >1.32$