As per the given figure, if ( dI / dt )=-1 A / s then the value of V AB at this instant will be V

Question

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0d9729b1907a172c5194a1644bd0dfdd-.png" /> As per the given figure, if ( dI / dt )=-1 A / s then the value of V AB at this instant will be V (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/0fb360a083af1bf020a365f94b5c4613-.png" /> ( dI / dt )=-1 ( A / sec ) VA-I R-L (d I/d t)-12=VB VA-2 × 12-6(-1)-12=VB VA-VB=36-6=30 volt

Q.
As per the given figure, if $\frac{d I}{d t} = - 1 A /$ s then the value of $V_{A B}$ at this instant will be ______ $V$

$\frac{d I}{d t} = - 1 \frac{A}{s e c}$
$V_{A} - I R - L \frac{d I}{d t} - 12 = V_{B}$
$V_{A} - 2 \times 12 - 6 (- 1) - 12 = V_{B}$
$V_{A} - V_{B} = 36 - 6 = 30$ volt

Q. As per the given figure, if dtdI​=−1A/ s then the value of VAB​ at this instant will be ______V

dtdI​=−1secA​ VA​−IR−LdtdI​−12=VB​ VA​−2×12−6(−1)−12=VB​ VA​−VB​=36−6=30 volt

Q.
As per the given figure, if $\frac{d I}{d t} = - 1 A /$ s then the value of $V_{A B}$ at this instant will be ______ $V$

$\frac{d I}{d t} = - 1 \frac{A}{s e c}$
$V_{A} - I R - L \frac{d I}{d t} - 12 = V_{B}$
$V_{A} - 2 \times 12 - 6 (- 1) - 12 = V_{B}$
$V_{A} - V_{B} = 36 - 6 = 30$ volt