As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be: ( g =10 m / s 2)

Question

As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be: ( g =10 m / s 2) (A) 4 m / s (B) 0 (C) 0.25 m / s (D) 2 m / s

Tardigrade Admin · Accepted Answer

The velocities will be interchanged after collision. Speed of P just before collision =√2 gh =√2 × 10 × 0.2=2 m / s

Q. As per the given figure, a small ball $P$ slides down the quadrant of a circle and hits the other ball $Q$ of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball $Q$ after collision will be : $(g = 10 m / s^{2})$

$4 m / s$

0

$0.25 m / s$

$2 m / s$

The velocities will be interchanged after collision.
Speed of $P$ just before collision $= 2 g h$
$= 2 \times 10 \times 0.2 = 2 m / s$

Q. As per the given figure, a small ball P slides down the quadrant of a circle and hits the other ball Q of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball Q after collision will be : (g=10m/s2)

4m/s

0

0.25m/s

2m/s

The velocities will be interchanged after collision. Speed of P just before collision =2gh​ =2×10×0.2​=2m/s

Q. As per the given figure, a small ball $P$ slides down the quadrant of a circle and hits the other ball $Q$ of equal mass which is initially at rest. Neglecting the effect of friction and assume the collision to be elastic, the velocity of ball $Q$ after collision will be : $(g = 10 m / s^{2})$

$4 m / s$

$0.25 m / s$

$2 m / s$

The velocities will be interchanged after collision.
Speed of $P$ just before collision $= 2 g h$
$= 2 \times 10 \times 0.2 = 2 m / s$