As per de-broglie formula a microscopic particle of mass 100 g and moving at a velocity of 100 cm / sec will have a wavelength of:

Question

As per de-broglie formula a microscopic particle of mass 100 g and moving at a velocity of 100 cm / sec will have a wavelength of: (A) 6.6 × 10-29 cm / s (B) 6.6 × 10-30 cm / s (C) 6.6 × 10-31 cm / s (D) 6.6 × 10-32 cm / s

Tardigrade Admin · Accepted Answer

According to De-Broglie equation;

Wavelength

(λ) = \frac{h}{m v}

Given;

m = 100 g, v = 100 c m / sec

h = 6.6 \times 1 0^{- 34} J s = 6.6 \times 1 0^{- 27} er g - s

on substituting values, we get

λ = \frac{6.6 \times 1 0 ^{- 27}}{100 \times 100}

= \frac{6.6 \times 1 0 ^{- 27}}{1 0 ^{4}}

= 6.6 \times 1 0^{- 31} c m / s

Q. As per de-broglie formula a microscopic particle of mass $100 g$ and moving at a velocity of $100 c m / sec$ will have a wavelength of:

$6.6 \times 1 0^{- 29} c m / s$

$6.6 \times 1 0^{- 30} c m / s$

$6.6 \times 1 0^{- 31} c m / s$

$6.6 \times 1 0^{- 32} c m / s$

Q. As per de-broglie formula a microscopic particle of mass 100g and moving at a velocity of 100cm/sec will have a wavelength of:

6.6×10−29cm/s

6.6×10−30cm/s

6.6×10−31cm/s

6.6×10−32cm/s

According to De-Broglie equation; Wavelength (λ)=mvh​ Given; m=100g,v=100cm/sec h=6.6×10−34Js=6.6×10−27erg−s on substituting values, we get λ=100×1006.6×10−27​ =1046.6×10−27​ =6.6×10−31cm/s

Q. As per de-broglie formula a microscopic particle of mass $100 g$ and moving at a velocity of $100 c m / sec$ will have a wavelength of:

$6.6 \times 1 0^{- 29} c m / s$

$6.6 \times 1 0^{- 30} c m / s$

$6.6 \times 1 0^{- 31} c m / s$

$6.6 \times 1 0^{- 32} c m / s$