Question

As a result of change in the magnetic flux linked to the closed loop shown in the figure, an emf $V$ volt is induced in the loop. The work done (joules) in taking a charge $Q$ coulomb once along the loop is

• A. Q V
• B. zero
• C. 2 QV
• D. $\frac{QV}{2}$

Answer 1

Answer: (A)

Induced emf
$=\frac{\text{ work done in taking a charge }Q\text{ once along the loop }}{\text{ charge }Q}$
i.e., $V=\frac{W}{Q}$
$\Rightarrow W=VQ$