Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. I. CH2 = CH - C6H4(NO2) II.CH2 = CH - C6H4(CH3) III. CH2 = CH - C6H4(OCH3)

Question

Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. I. CH2 = CH - C6H4(NO2) II.CH2 = CH - C6H4(CH3) III. CH2 = CH - C6H4(OCH3) (A) I > II > III (B) II > I > III (C) III > II > I (D) I > III > II

Tardigrade Admin · Accepted Answer

Electron releasing groups such as —CH3, —OCH3 activate the monomer towards cationic polymerisation because these groups provide stability to the carbocation formed. On the other hand, —NO2 is a electron withdrawing group. So, it reduces the stability of carbocation formed. Thus, the correct order is underset(III)CH2 = CH - C6H4(OCH3) > underset(II)CH2 = CH - C6H4(CH3) > underset(I)CH2 = CH -C6H4(NO2)

Q. Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation. I. CH2​=CH−C6​H4​(NO2​) II.CH2​=CH−C6​H4​(CH3​) III. CH2​=CH−C6​H4​(OCH3​)

I > II > III

II > I > III

III > II > I

I > III > II

Q. Arrange the following monomers in order of decreasing ability to undergo cationic polymerisation.
I. $C H_{2} = C H - C_{6} H_{4} (N O_{2})$
II. $C H_{2} = C H - C_{6} H_{4} (C H_{3})$
III. $C H_{2} = C H - C_{6} H_{4} (OC H_{3}$ )