Arrange the following molecules from most to least polar. CH4 CF2Cl2 CF2H2 CCl4 CH2Cl2 I II III IV V

Question

Arrange the following molecules from most to least polar. CH4 CF2Cl2 CF2H2 CCl4 CH2Cl2 I II III IV V (A) III > V > II > I = IV (B) II > IV > III > IV > I (C) III > II > V > IV > I (D) V > III > II > IV = I

Tardigrade Admin · Accepted Answer

(i) textlnC textH4 and textCC textl4 being tetrahedral (symmetrical molecules), bond dipoles cancel one other resulting in zero dipole moment. (ii) As electronegativity difference between two bonded atoms increases, the bond polarity increases resulting into the increase in dipole moment.

Q. Arrange the following molecules from most to least polar.

$C H_{4}$ $C F_{2} C l_{2}$ $C F_{2} H_{2}$ $CC l_{4}$ $C H_{2} C l_{2}$

I II III IV V

III > V > II > I = IV

II > IV > III > IV > I

III > II > V > IV > I

V > III > II > IV = I

(i) $lnC H_{4}$ and $CC l_{4}$ being tetrahedral (symmetrical molecules), bond dipoles cancel one other resulting in zero dipole moment.

(ii) As electronegativity difference between two bonded atoms increases, the bond polarity increases resulting into the increase in dipole moment.

Q. Arrange the following molecules from most to least polar. CH4​ CF2​Cl2​ CF2​H2​ CCl4​ CH2​Cl2​ I II III IV V