Arrange the following ions in the order of decreasing X-0 bond length, where X is the central atom in SiO44-,ClO4- ,PO43-,SO42-

Question

Arrange the following ions in the order of decreasing X-0 bond length, where X is the central atom in SiO44-,ClO4- ,PO43-,SO42- (A) ClO4- > SO42- > PO43- > SiO44- (B) SiO44- > PO43- > SO42- > ClO4- (C) SiO44- > PO43- > ClO4- > SO42-  (D) SiO44- > SO42- > PO43- > ClO4-

Tardigrade Admin · Accepted Answer

As the number of double bonds increases, X-O bond length decreases

Q. Arrange the following ions in the order of decreasing X-0 bond length, where X is the central atom in $S i O_{4}^{4 -}, Cl O_{4}^{-}, P O_{4}^{3 -}, S O_{4}^{2 -}$

$Cl O_{4}^{-} > S O_{4}^{2 -} > P O_{4}^{3 -} > S i O_{4}^{4 -}$

$S i O_{4}^{4 -} > P O_{4}^{3 -} > S O_{4}^{2 -} > Cl O_{4}^{-}$

$S i O_{4}^{4 -} > P O_{4}^{3 -} > Cl O_{4}^{-} > S O_{4}^{2 -}$

$S i O_{4}^{4 -} > S O_{4}^{2 -} > P O_{4}^{3 -} > Cl O_{4}^{-}$

$S O_{4}^{2 -} > P O_{4}^{3 -} > Cl O_{4}^{-} > S i O_{4}^{4 -}$

As the number of double bonds increases, X-O bond length decreases

Q. Arrange the following ions in the order of decreasing X-0 bond length, where X is the central atom in SiO44−​,ClO4−​,PO43−​,SO42−​

ClO4−​>SO42−​>PO43−​>SiO44−​

SiO44−​>PO43−​>SO42−​>ClO4−​

SiO44−​>PO43−​>ClO4−​>SO42−​

SiO44−​>SO42−​>PO43−​>ClO4−​

SO42−​>PO43−​>ClO4−​>SiO44−​

As the number of double bonds increases, X-O bond length decreases

Q. Arrange the following ions in the order of decreasing X-0 bond length, where X is the central atom in $S i O_{4}^{4 -}, Cl O_{4}^{-}, P O_{4}^{3 -}, S O_{4}^{2 -}$

$Cl O_{4}^{-} > S O_{4}^{2 -} > P O_{4}^{3 -} > S i O_{4}^{4 -}$

$S i O_{4}^{4 -} > P O_{4}^{3 -} > S O_{4}^{2 -} > Cl O_{4}^{-}$

$S i O_{4}^{4 -} > P O_{4}^{3 -} > Cl O_{4}^{-} > S O_{4}^{2 -}$

$S i O_{4}^{4 -} > S O_{4}^{2 -} > P O_{4}^{3 -} > Cl O_{4}^{-}$

$S O_{4}^{2 -} > P O_{4}^{3 -} > Cl O_{4}^{-} > S i O_{4}^{4 -}$