Arrange the following in the order of (i) increasing bond strength HCl, HBr, HF, HI (ii) increasing oxidation number of iodine I2,HI,HIO4,ICl

Question

Arrange the following in the order of (i) increasing bond strength HCl, HBr, HF, HI (ii) increasing oxidation number of iodine I2,HI,HIO4,ICl  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(i) Bond strength is inversely related to bond length. Hence, bond energy: HI < HBr < HCl < HF (ii) HI(- 1) < I2(O) < ICl(+1) < HIO4 (+7)

Q. Arrange the following in the order of
(i) increasing bond strength $H Cl, H B r, H F, H I$
(ii) increasing oxidation number of iodine
$I_{2}, H I, H I O_{4}, I Cl$

(i) Bond strength is inversely related to bond length. Hence,
bond energy : $H I < H B r < H Cl < H F$
$(ii) H I (- 1) < I_{2} (O) < I Cl (+ 1) < H I O_{4} (+ 7)$

Q. Arrange the following in the order of (i) increasing bond strength HCl,HBr,HF,HI (ii) increasing oxidation number of iodine I2​,HI,HIO4​,ICl

(i) Bond strength is inversely related to bond length. Hence, bond energy : HI<HBr<HCl<HF (ii)HI(−1)<I2​(O)<ICl(+1)<HIO4​(+7)

Q. Arrange the following in the order of
(i) increasing bond strength $H Cl, H B r, H F, H I$
(ii) increasing oxidation number of iodine
$I_{2}, H I, H I O_{4}, I Cl$

(i) Bond strength is inversely related to bond length. Hence,
bond energy : $H I < H B r < H Cl < H F$
$(ii) H I (- 1) < I_{2} (O) < I Cl (+ 1) < H I O_{4} (+ 7)$