Arrange the following in order of increasing dipole moment: H2O, H2S, BF3

Question

Arrange the following in order of increasing dipole moment: H2O, H2S, BF3 (A) BF3 < H2 S < H20 (B) H2S < BF3 < H20 (C) H20 < H2S < BF3 (D) BF 3 < H20 < H2S

Tardigrade Admin · Accepted Answer

In BF3, dipole moment is zero due to its symmetrical structure. Summations of all dipoles is zero. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/71cdb8b78d5ccd32dcba7edcd578c79f-.png" /> In H2S and H2O due to unsymmetrical structure net + ve dipole is there. H2O has higher dipole due to higher electronegativity of oxygen than sulphur.

Q. Arrange the following in order of increasing dipole moment: $H_{2} O, H_{2} S, B F_{3}$

$B F_{3} < H_{2} S < H_{2} 0$

$H_{2} S < B F_{3} < H_{2} 0$

$H_{2} 0 < H_{2} S < B F_{3}$

$B F_{3} < H_{2} 0 < H_{2} S$

In $B F_{3}$ , dipole moment is zero due to its symmetrical structure. Summations of all dipoles is zero.

In $H_{2} S$ and $H_{2} O$ due to unsymmetrical structure net $+$ ve dipole is there. $H_{2} O$ has higher dipole due to higher electronegativity of oxygen than sulphur.

Q. Arrange the following in order of increasing dipole moment: H2​O,H2​S,BF3​

BF3​<H2​S<H2​0

H2​S<BF3​<H2​0

H2​0<H2​S<BF3​

BF3​<H2​0<H2​S