Tardigrade
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Tardigrade
Question
Chemistry
Arrange the following in order of decreasing number of unpaired electrons? I. [ Fe ( H 2 O )6]2+ II. [ Fe ( CN )6]3- III. [ Fe ( CN )6]4- IV. [ Fe ( H 2 O )6]3+
Q. Arrange the following in order of decreasing number of unpaired electrons?
I.
[
F
e
(
H
2
O
)
6
]
2
+
II.
[
F
e
(
CN
)
6
]
3
−
III.
[
F
e
(
CN
)
6
]
4
−
IV.
[
F
e
(
H
2
O
)
6
]
3
+
3212
207
Coordination Compounds
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A
IV, I, II, III
B
I, II, III, IV
C
III, II, I, IV
D
II, III, I, IV
Solution:
(i)
[
F
e
(
H
2
O
)
6
]
2
+
,
3
d
6
n
=
4
(weak field ligand)
(ii)
[
F
e
(
CN
)
6
]
3
−
,
3
d
5
n
=
1
(Strong field ligand)
(iii)
[
F
e
(
CN
)
6
]
4
−
,
3
d
6
n
=
0
(strong field ligand)
(iv)
[
F
e
(
H
2
O
)
6
]
3
−
,
3
d
5
n
=
5
(weak field ligand)