Arrange the following in increasing order of bond length (i) N 2 (ii) N 2+ (iii) N 22+

Question

Arrange the following in increasing order of bond length (i) N 2 (ii) N 2+ (iii) N 22+ (A) (ii), (i) and (iii) (B) (ii), (iii) and (i) (C) (iii), (ii) and (i) (D) (i), (ii) and (iii)

Tardigrade Admin · Accepted Answer

As the bond order decreases, bond length increases Bond order

= \frac{No. of bonding e ^{-} s - No. of antibonding e ^{-} s}{2}

For

N_{2}

, electronic configuration is

σ 1 s^{2} < σ^{*} 1 s^{2} < σ 2 s^{2} < σ^{*} 2 s^{2} < (π 2 p_{x}^{2} = π 2 p_{y}^{2}) < 2 p_{z}^{2}

(i) Bond order of

N_{2} = \frac{10 - 4}{2} = 3

(ii) Bond order of

N_{2}^{+} = \frac{9 - 4}{2} = 2.5

(iii) Bond order of

N_{2}^{2 +} = \frac{8 - 4}{2} = 2

Hence, order of Bond length will be,

N_{2} < N_{2}^{+} < N_{2}^{2 +}

Q. Arrange the following in increasing order of bond length (i) N2​ (ii) N2+​ (iii) N22+​

(ii), (i) and (iii)

(ii), (iii) and (i)

(iii), (ii) and (i)

(i), (ii) and (iii)

Q. Arrange the following in increasing order of bond length
(i) $N_{2}$
(ii) $N_{2}^{+}$
(iii) $N_{2}^{2 +}$