Arrange the following compounds in decreasing order of acidity H2O, ROH, HC ≡ CH

Question

Arrange the following compounds in decreasing order of acidity H2O, ROH, HC ≡ CH (A) HC ≡ CH > ROH > H 2 O (B) H 2 O > ROH > HC ≡ CH (C) H 2 O > HC ≡ CH > ROH (D) ROH > H 2 O > HC ≡ CH

Tardigrade Admin · Accepted Answer

A stronger acid displaces a weaker acid from its salt. Since

H_{2} O

displaces

RO H

from

RON a

and both

H_{2} O

and alcohol displace acetylene from sodium acetylide, therefore, water is the strongest, followed by alcohol while acetylene is the weakest acid. In other words, acidity decreases in the order:

H_{2} O > RO H > H C \equiv C H

Q. Arrange the following compounds in decreasing order of acidity
$H_{2} O, RO H, H C \equiv C H$

$H C \equiv C H > RO H > H_{2} O$

$H_{2} O > RO H > H C \equiv C H$

$H_{2} O > H C \equiv C H > RO H$

$RO H > H_{2} O > H C \equiv C H$

Q. Arrange the following compounds in decreasing order of acidity H2​O,ROH,HC≡CH

HC≡CH>ROH>H2​O

H2​O>ROH>HC≡CH

H2​O>HC≡CH>ROH

ROH>H2​O>HC≡CH

Q. Arrange the following compounds in decreasing order of acidity
$H_{2} O, RO H, H C \equiv C H$

$H C \equiv C H > RO H > H_{2} O$

$H_{2} O > RO H > H C \equiv C H$

$H_{2} O > H C \equiv C H > RO H$

$RO H > H_{2} O > H C \equiv C H$