Arrange the following alcohols in the increasing order of reactivity with HBr. (I) benzyl alcohol (II) p-methyl benzyl alcohol (III) p-nitrobenzyl alcohol (IV)p-chlorobenzyl alcohol

Question

Arrange the following alcohols in the increasing order of reactivity with HBr. (I) benzyl alcohol (II) p-methyl benzyl alcohol (III) p-nitrobenzyl alcohol (IV)p-chlorobenzyl alcohol (A) I < II < III < IV (B) III < IV < I < II (C) II < I < IV < III (D) IV < III < II < I

Tardigrade Admin · Accepted Answer

Reactive intermediate carbocation is involved, hence greater the stability of carbocation, greater the reactivity of corresponding alcohols. <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/a16db7a1b696f6c741572512eb871f04-.jpeg" /> Stability order = B > A > D > C Reactivity = II > I > IV > III

Q. Arrange the following alcohols in the increasing order of reactivity with $H B r$ . (I) benzyl alcohol
(II) p-methyl benzyl alcohol
(III) p-nitrobenzyl alcohol
(IV)p-chlorobenzyl alcohol

$I < II < III < I V$

$III < I V < I < II$

$II < I < I V < III$

$I V < III < II < I$

Reactive intermediate carbocation is involved, hence greater the stability of carbocation, greater the reactivity of corresponding alcohols.

Stability order $= B > A > D > C$
Reactivity $= II > I > I V > III$

Q. Arrange the following alcohols in the increasing order of reactivity with HBr. (I) benzyl alcohol (II) p-methyl benzyl alcohol (III) p-nitrobenzyl alcohol (IV)p-chlorobenzyl alcohol

I<II<III<IV

III<IV<I<II

II<I<IV<III

IV<III<II<I