Question

Arrange in increasing order of solubility of AgBr in solutions given here
(i) 0.1 M $N{H}_3$ (ii) 0.1 M $AgN{O}_3$ (iii) 0.2 M NaBr (iv) pure water

• A. (iii) < (ii) < (iv) < (i)
• B. (iii) < (ii) < (i) < (iv)
• C. (iii) < (i) < (ii) < (iv)
• D. (ii) < (iii) < (iv) < (i)

Answer 1

Answer: (A)

AgBr $\to$ in $N{H}_3$ (Solubility increases, due to stable complex)
AgBr is highly soluble in ammonia due to complex formation.
$\to$ in 0.1 M $AgN{O}_3$ (Solubility decreases due to common ion effect)
$\to$ in 0.2 M NaBr (Solubility decreases more due to common ion effect)
$\to$ in pure water (Normal dissociation)
Hence, the order is:
(iii) < (ii) < (iv) < (i)