Arrange in increasing order of solubility of AgBr in solutions given here (i) 0.1 M NH3 (ii) 0.1 M AgNO3 (iii) 0.2 M NaBr (iv) pure water

Question

Arrange in increasing order of solubility of AgBr in solutions given here (i) 0.1 M NH3 (ii) 0.1 M AgNO3 (iii) 0.2 M NaBr (iv) pure water (A) (iii) < (ii) < (iv) < (i) (B) (iii) < (i) < (ii) < (iv) (C) (iii) < (ii) < (i) < (iv) (D) (ii) < (iii) < (iv) < (i)

Tardigrade Admin · Accepted Answer

AgBr arrow in NH3 (Solubility increases, due to stable complex) arrow in 0.1 M AgNO3 (Solubility decreases) arrow in 0.2 M NaBr (Solubility decreases more) arrow in pure water (Normal dissociation) Hence the order is (iii) < (ii) < (iv) < (i)

Q. Arrange in increasing order of solubility of AgBr in solutions given here

(i) 0.1 M $N H_{3}$ (ii) 0.1 M $A g N O_{3}$ (iii) 0.2 M NaBr (iv) pure water

(iii) < (ii) < (iv) < (i)

(iii) < (i) < (ii) < (iv)

(iii) < (ii) < (i) < (iv)

(ii) < (iii) < (iv) < (i)

AgBr $\to$ in $N H_{3}$ (Solubility increases, due to stable complex)

$\to$ in 0.1 M $A g N O_{3}$ (Solubility decreases)

$\to$ in 0.2 M NaBr (Solubility decreases more)

$\to$ in pure water (Normal dissociation)

Hence the order is

(iii) < (ii) < (iv) < (i)

Q. Arrange in increasing order of solubility of AgBr in solutions given here (i) 0.1 M NH3​ (ii) 0.1 M AgNO3​ (iii) 0.2 M NaBr (iv) pure water