Question

Arrange in increasing order of solubility of AgBr in solutions given here

(i) 0.1 M $NH_{3}$ (ii) 0.1 M $AgNO_{3}$ (iii) 0.2 M NaBr (iv) pure water

• A. (iii) < (ii) < (iv) < (i)
• B. (iii) < (i) < (ii) < (iv)
• C. (iii) < (ii) < (i) < (iv)
• D. (ii) < (iii) < (iv) < (i)

Answer 1

Answer: (A)

AgBr $ \rightarrow $ in $NH_{3}$ (Solubility increases, due to stable complex)

$ \rightarrow $ in 0.1 M $AgNO_{3}$ (Solubility decreases)

$ \rightarrow $ in 0.2 M NaBr (Solubility decreases more)

$ \rightarrow $ in pure water (Normal dissociation)

Hence the order is

(iii) < (ii) < (iv) < (i)