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Tardigrade
Question
Mathematics
Area of the region enclosed by y=x2 and y=√x is
Q. Area of the region enclosed by
y
=
x
2
and
y
=
x
is
3128
273
Application of Integrals
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A
1
sq. unit
B
2
1
sq. units
C
3
1
sq. units
D
cannot be determined
Solution:
We have,
y
=
x
2
...
(
i
)
a parabola with vertex
(
0
,
0
)
and
y
=
x
⇒
y
2
=
x
...
(
ii
)
a parabola with vertex
(
0
,
0
)
Point of intersection of
(
i
)
and
(
ii
)
is
(
0
,
0
)
and
(
1
,
1
)
Required area = area of shaded region
=
0
∫
1
(
x
−
x
2
)
d
x
=
[
3
2
x
3/2
−
3
1
x
3
]
0
1
=
3
1
sq. units