Aqueous solution of two compounds M1-O-H and M2-O-H are prepared in two different beakers. If the electronegativity of M1 = 3.4, M2 = 1.2,0 = 3.5 and H = 2.1, then the nature of two solution will be respectively

Question

Aqueous solution of two compounds M1-O-H and M2-O-H are prepared in two different beakers. If the electronegativity of M1 = 3.4, M2 = 1.2,0 = 3.5 and H = 2.1, then the nature of two solution will be respectively (A) Acidic, basic (B) acidic, acidic (C) basic, acidic (D) basic, basic

Tardigrade Admin · Accepted Answer

The electronegativity difference between M1 and O is 0.1, which indicates M1- O bond will be covalent, O - H bond having more ionic character will break and H+ ions will release, and acidic solution is formed. Whereas difference between electronegativity of M2 and O bond is 2.3 thus M2 - OH bond will break. Hence the solution will be basic in nature.

Q. Aqueous solution of two compounds M1​−O−H and M2​−O−H are prepared in two different beakers. If the electronegativity of M1​=3.4,M2​=1.2,0=3.5 and H=2.1, then the nature of two solution will be respectively

Acidic, basic

acidic, acidic

basic, acidic

basic, basic

Q. Aqueous solution of two compounds $M_{1} - O - H$ and $M_{2} - O - H$ are prepared in two different beakers. If the electronegativity of $M_{1} = 3.4, M_{2} = 1.2, 0 = 3.5$ and $H = 2.1$ , then the nature of two solution will be respectively