Anisole is treated with HI under two different conditions. C + D xleftarrow HI ( g )C 6 H 5 OCH 3 xrightarrow text conc.HI A + B The nature of A to D will be :

Question

Anisole is treated with HI under two different conditions. C + D xleftarrow HI ( g )C 6 H 5 OCH 3 xrightarrow text conc.HI A + B The nature of A to D will be : (A) A and B are CH 3 I and C 6 H 5 OH while C and D are CH 3 OH and C 6 H 5 I (B) A and B are CH 3 OH and C 6 H 5 I, while C and D are CH 3 I and C 6 H 5 OH (C) Both A and B as well as both C and D are CH 3 I and C 6 H 5 OH (D) A and B are CH 3 I and C 6 H 5 OH while there is no reaction in the second case

Tardigrade Admin · Accepted Answer

Although in both cases products are CH 3 I and C 6 H 5 OH; the two reactions follow different mechanism. C 6 H 5- O - CH 3 xrightarrow[HI(g)] S N 2CH 3 I + C 6 H 5 OH C 6 H 5- O - CH 3 xrightarrow[HI text(conc)] S N 1 CH 3 I + C 6 H 5 OH Remember that during S N 1 reaction, CH 3+is formed because it is more stable than C 6 H 5+.

Q. Anisole is treated with $H I$ under two different conditions.
$C + D H I (g) C_{6} H_{5} OC H_{3} conc.HI A + B$
The nature of $A$ to $D$ will be :

$A$ and $B$ are $C H_{3} I$ and $C_{6} H_{5} O H$ while $C$ and $D$ are $C H_{3} O H$ and $C_{6} H_{5} I$

$A$ and $B$ are $C H_{3} O H$ and $C_{6} H_{5} I$ , while $C$ and $D$ are $C H_{3} I$ and $C_{6} H_{5} O H$

Both $A$ and $B$ as well as both $C$ and $D$ are $C H_{3} I$ and $C_{6} H_{5} O H$

$A$ and $B$ are $C H_{3} I$ and $C_{6} H_{5} O H$ while there is no reaction in the second case

Q. Anisole is treated with HI under two different conditions. C+DHI(g)​C6​H5​OCH3​ conc.HI ​A+B The nature of A to D will be :

A and B are CH3​I and C6​H5​OH while C and D are CH3​OH and C6​H5​I

A and B are CH3​OH and C6​H5​I, while C and D are CH3​I and C6​H5​OH

Both A and B as well as both C and D are CH3​I and C6​H5​OH

A and B are CH3​I and C6​H5​OH while there is no reaction in the second case

Q. Anisole is treated with $H I$ under two different conditions.
$C + D H I (g) C_{6} H_{5} OC H_{3} conc.HI A + B$
The nature of $A$ to $D$ will be :

$A$ and $B$ are $C H_{3} I$ and $C_{6} H_{5} O H$ while $C$ and $D$ are $C H_{3} O H$ and $C_{6} H_{5} I$

$A$ and $B$ are $C H_{3} O H$ and $C_{6} H_{5} I$ , while $C$ and $D$ are $C H_{3} I$ and $C_{6} H_{5} O H$

Both $A$ and $B$ as well as both $C$ and $D$ are $C H_{3} I$ and $C_{6} H_{5} O H$

$A$ and $B$ are $C H_{3} I$ and $C_{6} H_{5} O H$ while there is no reaction in the second case