Aniline can be distinguished from methyl amine by its reaction with

Question

Aniline can be distinguished from methyl amine by its reaction with (A) p-toluene sulphonyl chloride/KOH (B) (i) NaNO 2 / HCl , 0-5° C (ii) alkaline β-naphthol (C) Sn/HCl (D) Acetyl chloride

Tardigrade Admin · Accepted Answer

Methyl amine when reacts with NaNO2 and textHCl gives N2 , while aniline gives diazonium salt. Diazonium salt so formed give red colour dye with alkaline β naphthol. Methyl amine however does not produce dye. So these two can be distinguished by using these reagents.

Q. Aniline can be distinguished from methyl amine by its reaction with

p-toluene sulphonyl chloride/KOH

(i) $N a N O_{2} / H Cl, 0 - 5^{\circ} C$
(ii) alkaline $β$ -naphthol

Sn/HCl

Acetyl chloride

Methyl amine when reacts with $N a N O_{2}$ and $HCl$ gives $N_{2}$ , while aniline gives diazonium salt. Diazonium salt so formed give red colour dye with alkaline $β$ naphthol. Methyl amine however does not produce dye. So these two can be distinguished by using these reagents.