Angular momentum of an electron in hydrogen atom is (3h/2π) (h is the Planckâs constant). The K.E. of the electron is

Question

Angular momentum of an electron in hydrogen atom is (3h/2π) (h is the Planckâs constant). The K.E. of the electron is (A) 4.35 eV (B) 1.51 eV (C) 3.4 eV (D) 6.8 eV

Tardigrade Admin · Accepted Answer

Angular momentum, L =( nh /2 π)=(3 h /2 π) given also n =3 ∴ E =(-1.36/ n 2) eV E =(-13.6/(3)2) eV E =(-13.6/9) eV E = -1.57 eV

Q. Angular momentum of an electron in hydrogen atom is $\frac{3 h}{2 π}$ (h is the Planck’s constant). The K.E. of the electron is

4.35 eV

1.51 eV

3.4 eV

6.8 eV

Angular momentum,
$L = \frac{nh}{2 π} = \frac{3 h}{2 π}$
$g i v e n$
also $n = 3$
$∴ E = \frac{- 1.36}{n ^{2}} e V$ $E = \frac{- 13.6}{( 3 ) ^{2}} e V$
$E = \frac{- 13.6}{9} e V$
$E = - 1.57 e V$

Q. Angular momentum of an electron in hydrogen atom is 2π3h​ (h is the Planck’s constant). The K.E. of the electron is