Angle strain in cyclopropane is

Question

Angle strain in cyclopropane is (A) 24° 44' (B) 9° 44' (C) 44' (D) -5° 16'

Tardigrade Admin · Accepted Answer

θ =[180-(360/n)]=[180-(360/3)] =180-120=60° Angle strain α =(1/2)[190° 28°-θ] =(1/2)[190° 28'-60°]=24° 44' Thus, Angle strain in cyclopropane is 24° 44'

Q. Angle strain in cyclopropane is

$2 4^{\circ} 4 4^{'}$

$9^{\circ} 4 4^{'}$

$4 4^{'}$

$- 5^{\circ} 1 6^{'}$

$θ = [180 - \frac{360}{n}] = [180 - \frac{360}{3}]$
$= 180 - 120 = 6 0^{\circ}$
Angle strain $α = \frac{1}{2} [19 0^{\circ} 2 8^{\circ} - θ]$
$= \frac{1}{2} [19 0^{\circ} 2 8^{'} - 6 0^{\circ}] = 2 4^{\circ} 4 4^{'}$
Thus, Angle strain in cyclopropane is $2 4^{\circ} 4 4^{'}$

Q. Angle strain in cyclopropane is

24∘44′

9∘44′

44′

−5∘16′

θ=[180−n360​]=[180−3360​] =180−120=60∘ Angle strain α=21​[190∘28∘−θ] =21​[190∘28′−60∘]=24∘44′ Thus, Angle strain in cyclopropane is 24∘44′

$2 4^{\circ} 4 4^{'}$

$9^{\circ} 4 4^{'}$

$4 4^{'}$

$- 5^{\circ} 1 6^{'}$

$θ = [180 - \frac{360}{n}] = [180 - \frac{360}{3}]$
$= 180 - 120 = 6 0^{\circ}$
Angle strain $α = \frac{1}{2} [19 0^{\circ} 2 8^{\circ} - θ]$
$= \frac{1}{2} [19 0^{\circ} 2 8^{'} - 6 0^{\circ}] = 2 4^{\circ} 4 4^{'}$
Thus, Angle strain in cyclopropane is $2 4^{\circ} 4 4^{'}$