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Q. Angle strain in cyclopropane is

AFMCAFMC 2011Hydrocarbons

Solution:

$ \theta =\left[180-\frac{360}{n}\right]=\left[180-\frac{360}{3}\right] $
$=180-120=60^{\circ}$
Angle strain $ \alpha =\frac{1}{2}\left[190^{\circ} 28^{\circ}-\theta\right] $
$=\frac{1}{2}\left[190^{\circ} 28'-60^{\circ}\right]=24^{\circ} 44'$
Thus, Angle strain in cyclopropane is $24^{\circ} 44'$