Angle of minimum deviation is equal to the angle of prism A of an equilateral glass prism. The angle of incidence at which minimum deviation will be obtained is

Question

Angle of minimum deviation is equal to the angle of prism A of an equilateral glass prism. The angle of incidence at which minimum deviation will be obtained is (A) 60° (B) 30° (C) 45° (D)  sin -1(2 / 3)

Tardigrade Admin · Accepted Answer

A=δm=60° At minimum deviation i=((A+δm/2))=60°

Q. Angle of minimum deviation is equal to the angle of prism $A$ of an equilateral glass prism. The angle of incidence at which minimum deviation will be obtained is

$6 0^{\circ}$

$3 0^{\circ}$

$4 5^{\circ}$

$sin^{- 1} (2/3)$

$A = δ_{m} = 6 0^{\circ}$
At minimum deviation $i = (\frac{A + δ _{m}}{2}) = 6 0^{\circ}$

Q. Angle of minimum deviation is equal to the angle of prism A of an equilateral glass prism. The angle of incidence at which minimum deviation will be obtained is

60∘

30∘

45∘

sin−1(2/3)