An X -ray tube with a copper target emits Cu Kα line of wavelength 1.50 mathringA. What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of X rays? (h=6.63 × 10-34 J - sec , c=3 × 108 m / s )

Question

An X -ray tube with a copper target emits Cu Kα line of wavelength 1.50 mathringA. What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of X rays? (h=6.63 × 10-34 J - sec , c=3 × 108 m / s ) (A) 8280 V (B) 828 V (C) 82800 V (D) 8.28 V

Tardigrade Admin · Accepted Answer

eV =(h c/λ) =(6.63 × 10-34 × 3 × 108/1.5 × 10-10) ⇒ V=(6.63 × 10-34 × 3 × 108/1.5 × 10-10) =8280 Volt

Q. An $X$ -ray tube with a copper target emits Cu $K_{α}$ line of wavelength $1.50 \overset{˚}{A}$ . What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of $X$ rays? $(h = 6.63 \times 1 0^{- 34} J - sec, c = 3 \times 1 0^{8} m / s)$

8280 V

828 V

82800 V

8.28 V

$e V = \frac{h c}{λ}$
$= \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{1.5 \times 1 0 ^{- 10}}$
$\Rightarrow V = \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{1.5 \times 1 0 ^{- 10}}$
$= 8280$ Volt

Q. An X -ray tube with a copper target emits Cu Kα​ line of wavelength 1.50A˚. What should be the minimum voltage through which electrons are to be accelerated to produce this wavelength of X rays? (h=6.63×10−34J−sec,c=3×108m/s)