An unknown metal of mass 192 g heated to a temperature of 100°C was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4°C Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5°C (Specific heat of brass is 394 J kg-1 K-1)

Question

An unknown metal of mass 192 g heated to a temperature of 100°C was immersed into a brass calorimeter of mass 128 g containing 240 g of water a temperature of 8.4°C Calculate the specific heat of the unknown metal if water temperature stabilizes at 21.5°C (Specific heat of brass is 394 J kg-1 K-1) (A) 1232 J kg-1 K-1 (B) 458 J kg-1 K-1 (C) 654 J kg-1 K-1 (D) 916 J kg-1 K-1

Tardigrade Admin · Accepted Answer

192 × S × (100 - 21.5) = 128 × 394 × (21.5 - 8.4) + 240 × 4200 × (21.5 - 8.4) ⇒ S = 916

$1232 J k g^{- 1} K^{- 1}$

$458 J k g^{- 1} K^{- 1}$

$654 J k g^{- 1} K^{- 1}$

$916 J k g^{- 1} K^{- 1}$

$192 \times S \times (100 - 21.5)$
$= 128 \times 394 \times (21.5 - 8.4)$
$+ 240 \times 4200 \times (21.5 - 8.4)$
$\Rightarrow S = 916$

1232Jkg−1K−1

458Jkg−1K−1

654Jkg−1K−1

916Jkg−1K−1

192×S×(100−21.5) =128×394×(21.5−8.4) +240×4200×(21.5−8.4) ⇒S=916

$1232 J k g^{- 1} K^{- 1}$

$458 J k g^{- 1} K^{- 1}$

$654 J k g^{- 1} K^{- 1}$

$916 J k g^{- 1} K^{- 1}$

$192 \times S \times (100 - 21.5)$
$= 128 \times 394 \times (21.5 - 8.4)$
$+ 240 \times 4200 \times (21.5 - 8.4)$
$\Rightarrow S = 916$