An unknown compound A has a molecular formula C4H6, when A is treated with an excess of Br2, a new substance B with formula C4H6Br4 is formed. A forms a white precipitate with ammoniacal silver nitrate solution. A may be

Question

An unknown compound A has a molecular formula C4H6, when A is treated with an excess of Br2, a new substance B with formula C4H6Br4 is formed. A forms a white precipitate with ammoniacal silver nitrate solution. A may be (A) Butyne-1 (B) Butyne - 2 (C) Butene - 1 (D) Butene - 2.

Tardigrade Admin · Accepted Answer

: Since A (C4H6) adds two moles of Br2 to give B (C4H6Br4) therefore, it is a butyne. Further since A forms a white ppt. with ammoniacal AgNO3 solution therefore, A is 1-butyne. CH3CH2C≡ CH+AgNO3+NH4OH xrightarrow[] underset(white text ppt.) mathopCH3CH2C ≡ CAg+NH4NO3+H2O

Q. An unknown compound A has a molecular formula C4​H6​, when A is treated with an excess of Br2​, a new substance B with formula C4​H6​Br4​ is formed. A forms a white precipitate with ammoniacal silver nitrate solution. A may be

Butyne-1

Butyne - 2

Butene - 1

Butene - 2.

: Since A (C4​H6​) adds two moles of Br2​ to give B (C4​H6​Br4​) therefore, it is a butyne. Further since A forms a white ppt. with ammoniacal AgNO3​ solution therefore, A is 1-butyne. CH3​CH2​C≡CH+AgNO3​+NH4​OH​ (whiteppt.)CH3​CH2​C​≡CAg+NH4​NO3​+H2​O

Q. An unknown compound A has a molecular formula $C_{4} H_{6},$ when A is treated with an excess of $B r_{2},$ a new substance B with formula $C_{4} H_{6} B r_{4}$ is formed. A forms a white precipitate with ammoniacal silver nitrate solution. A may be