An oxide of a metal (M) contains 40 % by mass of oxygen. Metal (M) has atomic mass of 24. The empirical formula of the oxide is-

Question

An oxide of a metal (M) contains 40 % by mass of oxygen. Metal (M) has atomic mass of 24. The empirical formula of the oxide is- (A) M 2 O (B) MO (C) M 2 O 3 (D) M 3 O 4

Tardigrade Admin · Accepted Answer

40 gm O present in 100 g metal oxide 16 g ---(100/40) × 16=40 g mol wt of metal oxide =40 g At wt of metal =24 g wt of oxygen =16 g ∴ Hence formula = MO

Q. An oxide of a metal (M) contains $40%$ by mass of oxygen. Metal (M) has atomic mass of 24. The empirical formula of the oxide is-

$M_{2} O$

$MO$

$M_{2} O_{3}$

$M_{3} O_{4}$

$40 g m O$ present in $100 g$ metal oxide

$16 g - - - \frac{100}{40} \times 16 = 40 g$

mol wt of metal oxide $= 40 g$

At wt of metal $= 24 g$

wt of oxygen $= 16 g$

$∴$ Hence formula $= MO$

Q. An oxide of a metal (M) contains 40% by mass of oxygen. Metal (M) has atomic mass of 24. The empirical formula of the oxide is-

M2​O

MO

M2​O3​

M3​O4​