1. Tardigrade
  2. Question
  3. Chemistry
  4. An organic compound X ( C 6 H 13 Br ) is optically active. X on treatment with ( CH 3)3 COK in ( CH 3)3 COH gives Y ( C 6 H 12), a major product. Y on treatment with Br 2- CCl 4 in the presence of FeBr 3 gives a dibromide which on further treatment with NaNH 2 gives C 6 H 10 which is still optically active. Hence, X and Y respectively are

Q. An organic compound is optically active. on treatment with in gives , a major product. on treatment with in the presence of gives a dibromide which on further treatment with gives which is still optically active. Hence, and respectively are

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Solution:

The last product formed after dehydrobromination is an alkyne. The only six carbon, optically active alkyne is

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