An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C , 38.71 % and H, 9.67 %. The empirical formula of the compound would be

Question

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C , 38.71 % and H, 9.67 %. The empirical formula of the compound would be (A) CHO (B) CH 4 O (C) CH 3 O (D) CH 2 O

Tardigrade Admin · Accepted Answer

Elements % At.mass Molar ratio Simplest ratio C 38.71 12 (38.71/12)=3.22 1 H 9.67 1 (9.67/1)=9.67 3 O 51.62 16 (51.67/16)=3.22 1 Therefore, empirical formula of the compound is CH3O

Q. An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave $C, 38.71%$ and $H$ , $9.67%$ . The empirical formula of the compound would be

$C H O$

$C H_{4} O$

$C H_{3} O$

$C H_{2} O$

Elements % At.mass Molar ratio Simplest ratio

C 38.71 12 $\frac{38.71}{12} = 3.22$ 1

H 9.67 1 $\frac{9.67}{1} = 9.67$ 3

O 51.62 16 $\frac{51.67}{16} = 3.22$ 1

Therefore, empirical formula of the compound is $C H_{3} O$

Elements	%	At.mass	Molar ratio	Simplest ratio
C	38.71	12	$\frac{38.71}{12} = 3.22$	1
H	9.67	1	$\frac{9.67}{1} = 9.67$	3
O	51.62	16	$\frac{51.67}{16} = 3.22$	1

Q. An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C,38.71% and H, 9.67%. The empirical formula of the compound would be

CHO

CH4​O

CH3​O

CH2​O