Q. An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave $C , 38.71 \%$ and $H$, $9.67 \%$. The empirical formula of the compound would be
Some Basic Concepts of Chemistry
Solution:
Elements
%
At.mass
Molar ratio
Simplest ratio
C
38.71
12
$\frac{38.71}{12}=3.22$
1
H
9.67
1
$\frac{9.67}{1}=9.67$
3
O
51.62
16
$\frac{51.67}{16}=3.22$
1
Therefore, empirical formula of the compound is $CH_{3}O$
Elements | % | At.mass | Molar ratio | Simplest ratio |
---|---|---|---|---|
C | 38.71 | 12 | $\frac{38.71}{12}=3.22$ | 1 |
H | 9.67 | 1 | $\frac{9.67}{1}=9.67$ | 3 |
O | 51.62 | 16 | $\frac{51.67}{16}=3.22$ | 1 |