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Q. An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave $C , 38.71 \%$ and $H$, $9.67 \%$. The empirical formula of the compound would be

Some Basic Concepts of Chemistry

Solution:

Elements % At.mass Molar ratio Simplest ratio
C 38.71 12 $\frac{38.71}{12}=3.22$ 1
H 9.67 1 $\frac{9.67}{1}=9.67$ 3
O 51.62 16 $\frac{51.67}{16}=3.22$ 1


Therefore, empirical formula of the compound is $CH_{3}O$