An organic compound containing C, H and N gave following analysis: C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be

Question

An organic compound containing C, H and N gave following analysis: C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be (A) C2H7N2 (B) CH5N (C) CH4N (D) C2H7N

Tardigrade Admin · Accepted Answer

beginmatrix textElement textNo. of moles& textSimple Ratio C=40 %&40 /12=3.33&1 H=13.33 %&13.33/ 1=13.33&4 N=46.67 %&7/ 14=3.33&1 endmatrix Thus formula CH4N

Q. An organic compound containing $C, H$ and N gave following analysis : C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be

$C_{2} H_{7} N_{2}$

$C H_{5} N$

$C H_{4} N$

$C_{2} H_{7} N$

$Element C = 40% H = 13.33% N = 46.67% No. of moles 40/12 = 3.33 13.33/1 = 13.33 7/14 = 3.33 Simple Ratio 141$
Thus formula $C H_{4} N$

Q. An organic compound containing C,H and N gave following analysis : C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be

C2​H7​N2​

CH5​N

CH4​N

C2​H7​N