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  4. An organic compound containing C, H and N gave following analysis: C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be

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Q. An organic compound containing $C, H $ and N gave following analysis : C = 40%, H = 13.33% and N = 46.67%. Its empirical formula would be

Organic Chemistry – Some Basic Principles and Techniques

Solution:

$\begin{matrix}{\text{Element}} &{\text{No. of moles}}&{\text{Simple Ratio}} \\ C=40\%&40 /12=3.33&1\\ H=13.33\%&13.33/ 1=13.33&4\\ N=46.67\%&7/ 14=3.33&1\end{matrix}$
Thus formula $CH_{4}N$