An organic compound containing C and H gave the following analysis C =40 %, H =6.7 %. Its empirical formula would be

Question

An organic compound containing C and H gave the following analysis C =40 %, H =6.7 %. Its empirical formula would be (A) CH 4 (B) CH 2 O (C) C 2 H 4 O 2. (D) C 2 H 4

Tardigrade Admin · Accepted Answer

% age Atomic mass Moles Simple ratio C 40 % 12 (40/12)= 3.33 1 H 6.7 % 1 (6.7/1)= 6.7 2 O 53.3 % 16 (53.3/16)= 3.33 1 ∴ EF = CH 2 O

	$%$ age	Atomic mass	Moles	Simple ratio
$C$	$40%$	$12$	$\frac{40}{12} = 3.33$	$1$
$H$	$6.7%$	$1$	$\frac{6.7}{1} = 6.7$	$2$
$O$	$53.3%$	$16$	$\frac{53.3}{16} = 3.33$	$1$

Q. An organic compound containing $C$ and $H$ gave the following analysis $C = 40%, H = 6.7%$ . Its empirical formula would be

$C H_{4}$

$C H_{2} O$

$C_{2} H_{4} O_{2}$ .

$C_{2} H_{4}$

$%$ age Atomic mass Moles Simple ratio

$C$ $40%$ $12$ $\frac{40}{12} = 3.33$ $1$

$H$ $6.7%$ $1$ $\frac{6.7}{1} = 6.7$ $2$

$O$ $53.3%$ $16$ $\frac{53.3}{16} = 3.33$ $1$

$∴ EF = C H_{2} O$

Q. An organic compound containing C and H gave the following analysis C=40%,H=6.7%. Its empirical formula would be

CH4​

CH2​O

C2​H4​O2​.

C2​H4​