An organic compound ( C 8 H 10 O 2) rotates plane-polarized light. It produces pink color with neutral FeCl 3 solution. What is the total number of all the possible isomers for this compound?

Question

An organic compound ( C 8 H 10 O 2) rotates plane-polarized light. It produces pink color with neutral FeCl 3 solution. What is the total number of all the possible isomers for this compound? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Since given compound produces pink colour with neutral

F e C l_{3}

.
So, it must have at least one

- O H

group attached to benzene ring.
Also, given compound is optically active, it means it should have a chiral centre, which is only possible when it has -

C H (O H) C H_{3}

So, based on the above observations, compound

(C_{8} H_{10} O_{2})

is expected to possess the following isomeric structures.

So, total isomeric structures

= 6

Q. An organic compound (C8​H10​O2​) rotates plane-polarized light. It produces pink color with neutral FeCl3​ solution. What is the total number of all the possible isomers for this compound?

Q. An organic compound $(C_{8} H_{10} O_{2})$ rotates plane-polarized light. It produces pink color with neutral $F e C l_{3}$ solution. What is the total number of all the possible isomers for this compound?