An organic compound 'A' has the molecular formula C3H6O, it undergoes iodoform 'test'. When saturated with HCl it gives 'B' of molecular formula C9H14O. A and B, respectively are

Question

An organic compound 'A' has the molecular formula C3H6O, it undergoes iodoform 'test'. When saturated with HCl it gives 'B' of molecular formula C9H14O. A and B, respectively are (A) Propanal and mesitylene (B) Propanone and mesityl oxide (C) Propanone and 2,6-dimethyl-2, 5-heptadien- 4-one (D) Propanone and mesitylene oxide

Tardigrade Admin · Accepted Answer

The compound A with formula C3H6O gives iodoform test, it is propanone. Further on saturation with HCl propanone forms a compound B having carbon atoms three times, the number of carbon atoms in propanone, it is phorone i.e., 2, 6-dimethyl-2, 5-heptadien-4-one.

Q. An organic compound $^{'} A^{'}$ has the molecular formula $C_{3} H_{6} O$ , it undergoes iodoform 'test'. When saturated with $H Cl$ it gives 'B' of molecular formula $C_{9} H_{14} O$ . A and B, respectively are

Propanal and mesitylene

Propanone and mesityl oxide

Propanone and 2,6-dimethyl-2, 5-heptadien- 4-one

Propanone and mesitylene oxide

The compound $A$ with formula $C_{3} H_{6} O$ gives iodoform test, it is propanone. Further on saturation with $H Cl$ propanone forms a compound $B$ having carbon atoms three times, the number of carbon atoms in propanone, it is phorone i.e., $2, 6 -$ dimethyl- $2$ , $5 -$ heptadien- $4$ -one.

Q. An organic compound ′A′ has the molecular formula C3​H6​O, it undergoes iodoform 'test'. When saturated with HCl it gives 'B' of molecular formula C9​H14​O. A and B, respectively are