1. Tardigrade
  2. Question
  3. Chemistry
  4. An organic compound 'A' has the molecular formula C3H6O, it undergoes iodoform 'test'. When saturated with HCl it gives 'B' of molecular formula C9H14O. A and B, respectively are

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An organic compound $'A'$ has the molecular formula $C_3H_6O$, it undergoes iodoform 'test'. When saturated with $HCl$ it gives 'B' of molecular formula $C_9H_{14}O$. A and B, respectively are

Aldehydes Ketones and Carboxylic Acids

Solution:

The compound $A$ with formula $C_3H_6O$ gives iodoform test, it is propanone. Further on saturation with $HCl$ propanone forms a compound $B$ having carbon atoms three times, the number of carbon atoms in propanone, it is phorone i.e., $2, 6-$dimethyl-$2$, $5-$heptadien-$4$-one.