An organ pipe with both ends open has a length L=25 cm. An extra hole is created at position (L/2), The lowest frequency of sound produced is (Assume speed of sound =340 m / s )

Question

An organ pipe with both ends open has a length L=25 cm. An extra hole is created at position (L/2), The lowest frequency of sound produced is (Assume speed of sound =340 m / s ) (A) 680 Hz (B) 340 Hz (C) 1360 Hz (D) 4352 Hz

Tardigrade Admin · Accepted Answer

We know that, there must be an antinode at the open end.
Since, a hole has been made at the position

\frac{L}{2}

,
so there must be another antinode at

x = \frac{L}{2}

For lowest frequency,

λ = L = 25 c m

Frequency of sound produced,

f = \frac{v}{λ} = \frac{340}{0.25} = 1360 Hz

Q. An organ pipe with both ends open has a length $L = 25 c m$ . An extra hole is created at position $\frac{L}{2}$ , The lowest frequency of sound produced is
(Assume speed of sound $= 340 m / s$ )

$680 Hz$

$340 Hz$

$1360 Hz$

$4352 Hz$

We know that, there must be an antinode at the open end.
Since, a hole has been made at the position $\frac{L}{2}$ ,
so there must be another antinode at $x = \frac{L}{2}$

For lowest frequency, $λ = L = 25 c m$
Frequency of sound produced,
$f = \frac{v}{λ} = \frac{340}{0.25} = 1360 Hz$

Q. An organ pipe with both ends open has a length L=25cm. An extra hole is created at position 2L​, The lowest frequency of sound produced is (Assume speed of sound =340m/s )

680Hz

340Hz

1360Hz

4352Hz