An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could be

Question

An optically active hydrocarbon X has molecular formula C6H12. X on catalytic hydrogenation gives optically inactive C6H14. X could be (A) 3-methyl-1-pentene (B) 3-methyl-2-pentene (C) 4-methyl-2-pentene (D) 2-ethyl-1 -butene

Tardigrade Admin · Accepted Answer

Correct answer is (a) 3-methyl-1-pentene

Q. An optically active hydrocarbon $X$ has molecular formula $C_{6} H_{12} . X$ on catalytic hydrogenation gives optically inactive $C_{6} H_{14} . X$ could be

$3$ -methyl- $1$ -pentene

$3$ -methyl- $2$ -pentene

$4$ -methyl- $2$ -pentene

$2$ -ethyl- $1$ -butene

Correct answer is (a) $3$ -methyl- $1$ -pentene

Q. An optically active hydrocarbon X has molecular formula C6​H12​.X on catalytic hydrogenation gives optically inactive C6​H14​.X could be

3-methyl-1-pentene

3-methyl-2-pentene

4-methyl-2-pentene

2-ethyl-1 -butene