Question

An open pipe resonates with a tuning fork of frequency $500Hz$ . It is observed that two successive nodes are formed at distances $16$ and $46cm$ from the open end. The speed of sound in air in the pipe is

• A. 230 m/s
• B. 300 m/s
• C. 320 m/s
• D. 360 m/s

Answer 1

Answer: (B)

Position of first node $=16cm$
$\frac{\lambda }{2}+e=16cm$ $\dots (i)$
Where, $e$= end correction
Position of second node $=46cm$
$\frac{\lambda }{2}+\frac{\lambda }{2}+e=46cm$ $\dots (ii)$
From Eqs. $(i)$ and $(ii)$, $\frac{\lambda }{2}=30cm$
$\lambda =60cm$
$=\frac{60}{100}m$
$\therefore$ Speed of sound, $V=n\lambda$
$=500\times \frac{60}{100}$ $(\because$ $n=500Hz$, Given)
$=300m/s$