An open organ pipe of length 33 cm, vibratos with frequency 1000 Hz. If velocity of sound in 330 m/s. Then its frequency is:

Question

An open organ pipe of length 33 cm, vibratos with frequency 1000 Hz. If velocity of sound in 330 m/s. Then its frequency is: (A) fundamental frequency (B) first overtone of pipe (C) second overtone (D) fourth overtone

Tardigrade Admin · Accepted Answer

Fundamental frequency n1 =(v/2 l) =(330/2 × 33 × 10-2) =500 Hz Frequency of Ist overtone =2 (v/2 l)=2 × 500 =1000 Hz

Q. An open organ pipe of length $33 c m,$ vibratos with frequency $1000 Hz$ . If velocity of sound in $330 m / s$ . Then its frequency is:

fundamental frequency

first overtone of pipe

second overtone

fourth overtone

Fundamental frequency
$n_{1} = \frac{v}{2 l}$
$= \frac{330}{2 \times 33 \times 1 0 ^{- 2}}$
$= 500 Hz$
Frequency of Ist overtone
$= 2 \frac{v}{2 l} = 2 \times 500$
$= 1000 Hz$

Q. An open organ pipe of length 33cm, vibratos with frequency 1000Hz. If velocity of sound in 330m/s. Then its frequency is: