An open capillary tube is lowered in a vessel with mercury. The difference between the levels of the mercury in the vessel and in the capillary tube is Δh= text4.6 mm . The radius of curvature of the mercury meniscus in the capillary tube will be (surface tension of mercury is text0.46 N m- 1 of mercury is text13.6 g cm- 3 )

Question

An open capillary tube is lowered in a vessel with mercury. The difference between the levels of the mercury in the vessel and in the capillary tube is Δh= text4.6 mm . The radius of curvature of the mercury meniscus in the capillary tube will be (surface tension of mercury is text0.46 N m- 1 of mercury is text13.6 g cm- 3 ) (A) (1/340)m (B) (1/680)m (C) (1/1020)m (D) information is insufficient

Tardigrade Admin · Accepted Answer

Îh=(2 Scos θ /rÏg)=(2 S/RÏg) ⇒ R=(2 S/ÎhÏg)

$\frac{1}{340} m$

$\frac{1}{680} m$

$\frac{1}{1020} m$

information is insufficient

$Δ h = \frac{2 S cos θ}{r ρ g} = \frac{2 S}{Rρ g}$
$\Rightarrow R = \frac{2 S}{Δ h ρ g}$

3401​m

6801​m

10201​m

information is insufficient

Δh=rρg2Scosθ​=Rρg2S​ ⇒R=Δhρg2S​

$\frac{1}{340} m$

$\frac{1}{680} m$

$\frac{1}{1020} m$

$Δ h = \frac{2 S cos θ}{r ρ g} = \frac{2 S}{Rρ g}$
$\Rightarrow R = \frac{2 S}{Δ h ρ g}$