An object of mass 5 kg is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 ms-2 is (g=10 text ms-2)

Question

An object of mass 5 kg is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 ms-2 is (g=10 text ms-2)  (A) 51.25 N (B) 48.75 N (C) 52.75 N (D) 47.25 N

Tardigrade Admin · Accepted Answer

On moving upward, weight, w=(mg+a)=5(10+0.25) =5× 10.25 =51.25N

Q. An object of mass $5 k g$ is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of $0.25$ $m s^{- 2}$ is $(g = 10 m s^{- 2})$

51.25 N

48.75 N

52.75 N

47.25 N

55 N

On moving upward, weight,
$w = (m g + a) = 5 (10 + 0.25)$ $= 5 \times 10.25$ $= 51.25 N$

Q. An object of mass 5kg is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 ms−2 is (g=10ms−2)