Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An object of mass $ 5\, kg $ is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of $ 0.25 $ $ m{{s}^{-2}} $ is $ (g=10\text{ }m{{s}^{-2}}) $

KEAMKEAM 2008Laws of Motion

Solution:

On moving upward, weight,
$ w=(mg+a)=5(10+0.25) $ $ =5\times 10.25 $ $ =51.25N $