An object of mass 4.237 g occupies a volume 1.72 cm 3. The density of the object to appropriate significant figures is

Question

An object of mass 4.237 g occupies a volume 1.72 cm 3. The density of the object to appropriate significant figures is (A) 2.46 g cm -3 (B) 2.463 g cm -3 (C) 2.5 g cm -3 (D) 2.50 g cm -3

Tardigrade Admin · Accepted Answer

m=4.237 g V=1.72 cm 3 Density =( text Mass / text Volume )=(4.237 g /1.72 cm 3) ⇒ d=2.46 g cm -3

Q. An object of mass $4.237 g$ occupies a volume $1.72 c m^{3}$ . The density of the object to appropriate significant figures is

$2.46 g c m^{- 3}$

$2.463 g c m^{- 3}$

$2.5 g c m^{- 3}$

$2.50 g c m^{- 3}$

$m = 4.237 g$
$V = 1.72 c m^{3}$
Density $= \frac{Mass}{Volume} = \frac{4.237 g}{1.72 c m ^{3}}$
$\Rightarrow d = 2.46 g c m^{- 3}$

Q. An object of mass 4.237g occupies a volume 1.72cm3. The density of the object to appropriate significant figures is

2.46gcm−3

2.463gcm−3

2.5gcm−3

2.50gcm−3