An object of mass 10 kg is projected from ground with speed 40 m / s at an angle 60° with horizontal. The rate of change of momentum of object one second after projection in SI unit is [Take g=9.8 m / s 2 ]

Question

An object of mass 10 kg is projected from ground with speed 40 m / s at an angle 60° with horizontal. The rate of change of momentum of object one second after projection in SI unit is [Take g=9.8 m / s 2 ] (A) 73 (B) 98 (C) 176 (D) 140

Tardigrade Admin · Accepted Answer

Force =(Δ p/ Δ t ), force remains constant =m g ⇒ 10 × 9.8 ⇒ 98 N At t=1, particle is at its maximum height.

Q. An object of mass $10 k g$ is projected from ground with speed $40 m / s$ at an angle $6 0^{\circ}$ with horizontal. The rate of change of momentum of object one second after projection in $S I$ unit is [Take $g = 9.8 m / s^{2}$ ]

73

98

176

140

Force $= \frac{Δ p}{Δ t}$ , force remains constant $= m g$
$\Rightarrow 10 \times 9.8$
$\Rightarrow 98 N$
At $t = 1$ , particle is at its maximum height.

Q. An object of mass 10kg is projected from ground with speed 40m/s at an angle 60∘ with horizontal. The rate of change of momentum of object one second after projection in SI unit is [Take g=9.8m/s2 ]

73

98

176

140

Force =ΔtΔp​, force remains constant =mg ⇒10×9.8 ⇒98N At t=1, particle is at its maximum height.

Q. An object of mass $10 k g$ is projected from ground with speed $40 m / s$ at an angle $6 0^{\circ}$ with horizontal. The rate of change of momentum of object one second after projection in $S I$ unit is [Take $g = 9.8 m / s^{2}$ ]

Force $= \frac{Δ p}{Δ t}$ , force remains constant $= m g$
$\Rightarrow 10 \times 9.8$
$\Rightarrow 98 N$
At $t = 1$ , particle is at its maximum height.