An object of mass 10 kg is connected to the lower end of a massless string of length 4 m hanging from the ceiling. If a force F is applied horizontally at the mid-point of the string, the top half of the string makes an angle of 45° with the vertical, then the magnitude of F is

Question

An object of mass 10 kg is connected to the lower end of a massless string of length 4 m hanging from the ceiling. If a force F is applied horizontally at the mid-point of the string, the top half of the string makes an angle of 45° with the vertical, then the magnitude of F is (A) 75 N (B) 90N (C) 100 N (D) 70N

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-rin2jhsohbiv.png" /> (T/√2)=100 (T/√2)=F F=100 N

Q. An object of mass $10 k g$ is connected to the lower end of a massless string of length $4 m$ hanging from the ceiling. If a force $F$ is applied horizontally at the mid-point of the string, the top half of the string makes an angle of $4 5^{\circ}$ with the vertical, then the magnitude of $F$ is

$75 N$

$90 N$

$100 N$

$70 N$

$\frac{T}{2} = 100$
$\frac{T}{2} = F$
$F = 100 N$

Q. An object of mass 10kg is connected to the lower end of a massless string of length 4m hanging from the ceiling. If a force F is applied horizontally at the mid-point of the string, the top half of the string makes an angle of 45∘ with the vertical, then the magnitude of F is

75N

90N

100N

70N

2​T​=100 2​T​=F F=100N

$75 N$

$90 N$

$100 N$

$70 N$

$\frac{T}{2} = 100$
$\frac{T}{2} = F$
$F = 100 N$