An object is resting at the bottom of two strings which are inclined at an angle of 120° with each other. Each string can withstand a tension of 20 N. The maximum weight of the object that can be supported without breaking the string is

Question

An object is resting at the bottom of two strings which are inclined at an angle of 120° with each other. Each string can withstand a tension of 20 N. The maximum weight of the object that can be supported without breaking the string is (A) 5 N (B) 10 N (C) 20 N (D) 40 N

Tardigrade Admin · Accepted Answer

W=2 T cos 60° W max =2 T max cos 60° =2(20 N )((1/2))=20 N

Q. An object is resting at the bottom of two strings which are inclined at an angle of $12 0^{\circ}$ with each other. Each string can withstand a tension of $20 N$ . The maximum weight of the object that can be supported without breaking the string is

5 N

10 N

20 N

40 N

$W = 2 T cos 6 0^{\circ}$
$W_{m a x} = 2 T_{m a x} cos 6 0^{\circ}$
$= 2 (20 N) (\frac{1}{2}) = 20 N$

Q. An object is resting at the bottom of two strings which are inclined at an angle of 120∘ with each other. Each string can withstand a tension of 20N. The maximum weight of the object that can be supported without breaking the string is

5 N

10 N

20 N

40 N

W=2Tcos60∘ Wmax​=2Tmax​cos60∘ =2(20N)(21​)=20N

Q. An object is resting at the bottom of two strings which are inclined at an angle of $12 0^{\circ}$ with each other. Each string can withstand a tension of $20 N$ . The maximum weight of the object that can be supported without breaking the string is

$W = 2 T cos 6 0^{\circ}$
$W_{m a x} = 2 T_{m a x} cos 6 0^{\circ}$
$= 2 (20 N) (\frac{1}{2}) = 20 N$